Preclinics of Dental Prosthetics · MU Sofia

22. Functional-mechanical equilibrium of the periodontium. Physiologic tolerance and loading limits.

Explains Balabanov's concept of functional-mechanical equilibrium of the periodontium, in which a root can carry its own occlusal surface plus one more, and how Popov's modification applies this ratio to fixed bridge planning. Includes a diagram of a three-unit bridge, a worked abutment example with the occlusal table narrowed by about 30%, and a table of conditions that lower periodontal tolerance. Also compares the approach with Ante's law.

Inside: 4 sections · 1 labelled picture · 1 table · 2 formulas · 16 flashcards · 3 min

Topic 22 of 75 in the MU Sofia syllabus for Preclinics of Dental Prosthetics (Dental Medicine, Year 2). The free AceMed note covers it in 4 sections, about 290 words (3 min of reading), with 16 flashcards.

In this note

  1. Introduction
  2. The concept
  3. Applied to fixed bridges (Popov's modification)
  4. Physiologic tolerance and loading limits

Introduction

Every abutment tooth can carry more than its own load, but not unlimited load. Bulgarian prosthodontics answers "how much more?" with Balabanov's concept of the functional-mechanical equilibrium of the periodontium (1970), used in clinical practice for more than 40 years.

The concept

The periodontium of a natural tooth is in functional and mechanical equilibrium when the ratio between the area of its occlusal surface and the area of its active root surface stays constant.

Balabanov calculated this constant as:

Fₒ is the occlusal surface area and Fₚ the periodontal (root) surface area. In plain words: a healthy root can carry two occlusal surfaces, its own and one more. The second one is the tooth's reserve force.

Applied to fixed bridges (Popov's modification)

Planning a bridge means solving two problems: choosing the abutments and designing the restoration. For an optimal result, the total occlusal area of retainers and pontics must relate to the total root area of the abutments within:

For bridges on natural teeth this means one abutment may carry one pontic.

Worked example

Tooth 35 is missing; 34 and 36 are healthy with normal mobility.

  1. Abutments: 34 and 36.
  2. Occlusal load: Fₒ34 + Fₒ35 + Fₒ36 = 3Fₒ.
  3. Root support: Fₚ34 + Fₚ36 = 2Fₚ.
  4. Ratio: 3Fₒ/2Fₚ = 1.5, which is less than 2: acceptable.
  5. The occlusal tables of retainers and pontic are narrowed by about 30%, because full-width surfaces would overload the abutments.

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